Transforming XML file: NeuroMLFiles/Examples/ChannelML/KChannel_HH.xml using XSL file: NeuroMLFiles/Schemata/v1.8.1/Level3/NeuroML_Level3_v1.8.1_HTML.xsl

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Converting the file: KChannel_HH.xml

General notes
Notes present in ChannelML file
ChannelML file containing a single Channel description

Unit system of ChannelML file
This can be either SI Units or Physiological Units (milliseconds, centimeters, millivolts, etc.)
Physiological Units

Channel: KConductance

Status of element in file
Comment: Equations adapted from HH paper for modern convention of external potential being zero
Contributor: Padraig Gleeson
As described in the ChannelML file
Simple example of K conductance in squid giant axon. Based on channel from Hodgkin and Huxley 1952
Translators of the model to NeuroML:
   Padraig Gleeson  (UCL)  p.gleeson - at -
Referenced publicationA. L. Hodgkin and A. F. Huxley, A quantitative description of membrane current and its application to conduction and excitation in nerve, J. Physiol., vol. 117, pp. 500-544, 1952. Pubmed
Reference in NeuronDB K channels
Current voltage relationshipohmic
Ion involved in channel
The ion which is actually flowing through the channel and its default reversal potential. Note that the reversal potential will normally depend on the internal and external concentrations of the ion at the segment on which the channel is placed.
k (default Ek = -77.0 mV)
Default maximum conductance density
Note that the conductance density of the channel will be set when it is placed on the cell.
Gmax = 36 mS cm-2
Conductance expression
Expression giving the actual conductance as a function of time and voltage
Gk(v,t) = Gmax * n(v,t) 4
Current due to channel
Ionic current through the channel
Ik(v,t) = Gk(v,t) * (v - Ek)

Gate: n

The equations below determine the dynamics of gating state n

Instances of gating elements4
Closed staten0
Open staten
    Transition: alpha from n0 to n
Expressionalpha(v) = A*((v-V1/2)/B) / (1 - exp(-(v-V1/2)/B))    (exp_linear)
Parameter values A = 0.1 ms-1   B = 10 mV   V1/2 = -55 mV
alpha(v) = 0.1 * ( v - (-55)) / 10
1- e -(( v - (-55)) / 10)
    Transition: beta from n to n0
Expressionbeta(v) = A*exp((v-V1/2)/B)    (exponential)
Parameter values A = 0.125 ms-1   B = -80 mV   V1/2 = -65 mV
Substituted beta(v) = 0.125 * e (v - (-65))/-80

Time to transform file: 0.116 secs